Splet24. feb. 2024 · Consider the lines given by. L 1: x + 3y - 5 = 0. L 2: 3x - ky - 1 = 0. L 3: 5x + 2y - 12 = 0. Column I: Column II (A) L 1,L 2,L 3 are concurrent, if ... Lines L1 L2 given by y –x = 0 and 2x + y = 0 intersect the line L3 given by y + 2 = 0 at P and Q, respectively. asked Dec 6, 2024 in Straight Lines by LuciferKrish (53.9k points) straight ... SpletThe line L given by x/5 + y/b = 1 passes through the point (13, 32). If the line K is parallel to L and has the equation x/c + y/3 = 1 , then the distance between L and K is Class 11 >> …
Let $L$ be the line of intersection between two planes
SpletSo we first find the equation of the line through (2,9) that is perpendicular to the line y = 7x + 2. Since the line y = 7x + 2 has slope 7, the desired line (that is, line AB) has slope -1/7 as well as passing through (2,9). So the desired line has an equation of the form y = (-1/7)x + b. Substituting the point (2,9) gives Splet(x/a) + (y/b) = 1. Thus, this is the equation of line in intercept form. Method 3: Suppose the line L meets x-axis at the point A(a, 0) and y-axis at the point B(0, b), respectively. So, the x-intercept is a and y-intercept is b. Let P(x, y) be the point on the line L such that the points A, P and B are collinear. hormonchip pferd
The line L given by (x/5) + (y/b) = 1 passes through the point (13, …
SpletSolution The line L given by x 5 + y b = 1 passes through the point (13, 32). The line K is parallel to L and its equation is x c + y 3 = 1. Then, the distance between L and K is 23 17. Explanation: Line L passes through (13, 32). ∴ 13 5 + 32 b = 1 ⇒ b = -20 So,equation of L is x 5 - y 20 = 1 ⇒ 4x - y = 20 Slope of L is m 1 = 4. Splet12. okt. 2024 · But, if it's less than one, then it becomes less steep (0 < m < 1). Looking at the graph, the graph looks relatively steep (graphing the equations y = 5/7 x - 3/2 and y = 7/5x - 3/2 can help you see the differences between them). Therefore, the equation of the line given by the graph is choice D, y = 7/5 x − 3/2. SpletFind the distance from the point P ( 3, − 1, 4) and the line whose parametric equations are: x = − 2 + 3 t, y = − 2 t, and z = 1 + 4 t I'm not completely sure how to solve this so I first gave the parameter t some initial values: t = 0 = Q ( − 2, 0, 1) t = 1 = R ( 1, − 2, 5) Q R → = 1 + 2, − 2 − 0, 5 − 1 = 3, − 2, 4 lost ark female names